Checking for target while imaging, as I nearly always do, I spied a tiny galaxy in a pretty dark portion of the sky, NGC6166.
Solved with annotations
While processing this portion of our universe I spied galaxies: NGC6166, UGC10404, PGC058277, NGC6158 and SDSS J162915.46+392226.4. The latter of which is listed as a galaxy with these measured values
Radial velocity / Redshift / cz : V(km/s) 83829 [54] / z(spectroscopic) 0.33279 [0.00018] / cz 99768.0 [54.0]
And RA/DEC of
16 29 15.462 +39 22 26.41
Per
https://simbad.cds.unistra.fr/simbad/sim-id?Ident=%406143502&Name=SDSS%20J162915.46%2b392226.4&submit=submit
Running the calculations via Microsoft Copilot AI, it gave me a distance of 3.9 Billion LY!!
if the rv = 83829 what is the distance in millions of light years?
Let's calculate the approximate distance using the Hubble's Law, which states:
[ D = \frac{V}{H_0} ]
where:
• ( D ) is the distance in megaparsecs (Mpc),
• ( V ) is the radial velocity (here, 83,829 km/s),
• ( H_0 ) is the Hubble constant, typically around 70 km/s/Mpc (but exact value varies based on cosmological models).
Step 1: Convert radial velocity to distance in Mpc
[ D = \frac{83829}{70} \approx 1197 \text{ Mpc} ]
Step 2: Convert Mpc to millions of light-years
Since 1 Mpc ≈ 3.26 million light-years, we get:
[ D (\text{millions of light-years}) = 1197 \times 3.26 ]
[ \approx 3905 \text{ million light-years} ]
So, the object is roughly 3.9 billion light-years away! Keep in mind that this is a simplified estimate based on the Hubble Law; more precise distances depend on detailed cosmological models. Let me know if you'd like to explore those too!
Here's the closeup measured and found in ASTAP
